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The area of this isosceles triangle is 8cm2.

The angle ABC is 27o.

 

Work out the length of x.

Give the answer to 1 d.p. or better.

 

Guest Apr 1, 2017
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 #1
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We can find x as follows :

 

Area =  (1/2) * x^2 * sin(27°)

 

8  =  (1/2) * x^2 * sin(27°)       multiply both sides by 2

 

16  = x^2 * sin (27°)    divide both sides by sin (27°)

 

[ 16 / sin (27°) ]  = x^2         take the square root of both sides

 

sqrt [ 16 / sin (27°) ]   = x  ≈  5.937  cm^2

 

 

cool cool cool

CPhill  Apr 1, 2017

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