The length of a rectangle is 3 ft more than twice the width, and the area of the rectangle is 77 ft2 . Find the dimensions of the rectangle.
Let L represent length W represent width and A represent area.
Since the length is 3 ft more than twice the width, we can write this as L = 3 + 2W
The formula for the area of a rectangle is A = L x W
Since the area is 77, 77 = L x W
Substituting: 77 = (3 + 2W) x W
Multiplying out: 77 = 3W + 2W²
Rewriting: 2W² + 3W = 77
Subtracting: 2W² + 3W - 77 = 0
Factoring: (2W - 11)(W + 7) = 0
So, either 2W - 11 = 0 ---> 2W = 11 ---> W = 5.5 ft
or W + 7 = 0 ---> W = -7 (not possible)
Since L = 3 + 2W ---> L = 3 + 2(5.5) = 14 ft
Let L represent length W represent width and A represent area.
Since the length is 3 ft more than twice the width, we can write this as L = 3 + 2W
The formula for the area of a rectangle is A = L x W
Since the area is 77, 77 = L x W
Substituting: 77 = (3 + 2W) x W
Multiplying out: 77 = 3W + 2W²
Rewriting: 2W² + 3W = 77
Subtracting: 2W² + 3W - 77 = 0
Factoring: (2W - 11)(W + 7) = 0
So, either 2W - 11 = 0 ---> 2W = 11 ---> W = 5.5 ft
or W + 7 = 0 ---> W = -7 (not possible)
Since L = 3 + 2W ---> L = 3 + 2(5.5) = 14 ft