The length of a rectangle is 6 yd longer than its width. If the perimeter of the rectangle is 44 yd , find its area.
Let L represent length.
Let W represent width.
Since the length is 6 yd longer than its width: L = 6 + W
The formula for perimeter: P = 2L + 2W
Since the perimeter is 44 yds: 44 = 2L + 2W
Substituting: 44 = 2(6 + W) + 2W
44 = 12 + 2W + 2W
44 = 12 + 4W
32 = 4W
W = 8 yds
Since L = 6 + W ---> L = 14 yds
Let L represent length.
Let W represent width.
Since the length is 6 yd longer than its width: L = 6 + W
The formula for perimeter: P = 2L + 2W
Since the perimeter is 44 yds: 44 = 2L + 2W
Substituting: 44 = 2(6 + W) + 2W
44 = 12 + 2W + 2W
44 = 12 + 4W
32 = 4W
W = 8 yds
Since L = 6 + W ---> L = 14 yds