+128475 The two radii are equal sides of an isosceles triangle. So the angles opposite those sides (A and B) are equal. Thus, angle A + angle B + 110 = 180. So, angle A + angle A + 110 = 180. Subtract 110 from each side. Thus angle A + angle A = 180-110. So 2*angle A = 70. Divide by 2 on both sides. Then, angle A = (70)/2 = 35 degrees.
+128475 The two radii are equal sides of an isosceles triangle. So the angles opposite those sides (A and B) are equal. Thus, angle A + angle B + 110 = 180. So, angle A + angle A + 110 = 180. Subtract 110 from each side. Thus angle A + angle A = 180-110. So 2*angle A = 70. Divide by 2 on both sides. Then, angle A = (70)/2 = 35 degrees.
+8261 CPhill, I am a bit confused on this one. May you please explain it to me?
+128475 OK, DS......we have a triangle ABC where one angle = 110 degrees. Note that two of the sides are just radii of the circle. And all radii in a circle are equal. And by a theorem in Gepmetry, when two sides of a triangle are equal, the angles opposite those sides (in this case, angle A and angle B) are equal. So remember , that in any triangle, the angles always sum to 180 degrees. So angle A + angle B + 110 = 180. But angle A = angle B, so we can write......angle A + angle A + 110 = 180. Therefore 2*Angle A + 110 = 180. Subtract 110 from each side, and we have....2*Angle A = 70. Now, divide both sides by 2, and we have that Angle A = 35.
Got it???
+8261 I don't get what radii is and I don't know what Gepmetry is. May you explain those so I can understand it?
