The shorter leg of a right triangle is 8 inches shorter than the longer leg. The hypotenuse is 8 inches longer than the longer leg. Find the side lengths of the triangle.
Legnth Of the shorter leg: ?
Legnth of the longer leg: ?
Legnth of the hypotenuse: ?
Let L represent the length of the longer leg.
Then L - 8 represents the length of the shorter leg and L + 8 represents the length of the longer leg.
Using the Pythagorean theorem: (L)² + (L - 8)² = (L + 8)²
Multiplying out: L² + L² - 16L + 64 = L² + 16L + 64
Subtract 64 from both sides: L² + L² - 16L = L² + 16L
Subtract L² from both sides: L² - 16L = 16L
Subtract 16L from both sides: L² - 32L = 0
Factor: L(L - 32) = 0
Either L = 0 (impossible) or L - 32 = 0 ---> L = 32
If L = 32, then L - 8 = 24 and L + 8 = 40
Let L represent the length of the longer leg.
Then L - 8 represents the length of the shorter leg and L + 8 represents the length of the longer leg.
Using the Pythagorean theorem: (L)² + (L - 8)² = (L + 8)²
Multiplying out: L² + L² - 16L + 64 = L² + 16L + 64
Subtract 64 from both sides: L² + L² - 16L = L² + 16L
Subtract L² from both sides: L² - 16L = 16L
Subtract 16L from both sides: L² - 32L = 0
Factor: L(L - 32) = 0
Either L = 0 (impossible) or L - 32 = 0 ---> L = 32
If L = 32, then L - 8 = 24 and L + 8 = 40