+0  
 
+10
1394
4
avatar+556 

There are seven wombats in a council. Three of them are hairy-nosed wombats, while the rest are all different species. If the hairy-nosed wombats are indistinguishable but the other wombats are, how many ways can the wombats seat themselves in a row?

 Dec 30, 2016

Best Answer 

 #2
avatar
+10

35, or 7! / 3!*4!. This is equal to the number of ways that a group of 3 objects can fill seven cells,

with the remaining 4 objects mixed in.

 Dec 31, 2016
 #1
avatar+355 
+5

You can position all of the wombats in 7! ways BUT you have over counted the 3 hairy wombats. So the answer is:

 

7!/3! = 840 

 Dec 30, 2016
 #2
avatar
+10
Best Answer

35, or 7! / 3!*4!. This is equal to the number of ways that a group of 3 objects can fill seven cells,

with the remaining 4 objects mixed in.

Guest Dec 31, 2016
 #3
avatar+118613 
0

There are seven wombats in a council. Three of them are hairy-nosed wombats, while the rest are all different species. If the hairy-nosed wombats are indistinguishable but the other wombats are, how many ways can the wombats seat themselves in a row?

The real meaning of this question is difficult to determine....

I think that both answers have merit.

 

there are 840 different ways that the wombats can sit, just like NinjaAnswer said,

but if you only care about the position of the 3 hairy nose wombats then I think out guest is correct.  :)

 Jan 1, 2017
 #4
avatar+556 
0

A fair coin is flipped 7 times. What is the probability that at least 5 consecutive flips come up heads?

 Jan 2, 2017

3 Online Users