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Triangle ABC is an isosceles triangle with side lengths of 25, 25 and 48 centimeters. What is the area of triangle ABC, in square centimeters?

 
Guest Nov 14, 2017
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 #1
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25 units = a line segment starting at (-24, 0) and ending at (0, n)

Pythagorean theorem: \(625 = 576 - n^2\)

625 - 576 = 49

\(\sqrt{49} = 7\)

n = 7

Now that we have the height and the width, we solve using \(a = \frac{1}{2}bh\)

\(7 \times 48 \div 2=7\times 24 = 168\)

The area of the triangle is 168 square centimeters.

 

 

^^^ I honestly don't know how I managed to use that method. ^^^

 
helperid1839321  Nov 14, 2017
 #2
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lol. haha. good job that was correct.

 
Guest Nov 14, 2017

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