How would you solve this trig equation? 3cos x - 2 = cos x ???? The directions say: solve equations for 0 < x <360.
3cos x - 2 = cos x
\(3cos x - 2 = cos x\\ 2cos x - 2 = 0\\ 2cos x =2\\ cosx =1\\ x = 0,360\\ \mbox{there are no solutions for x where }0<x<360\)
