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Find sin2A when tanA = 1/3 and π<A<3π/2.








 


A) 3/5








B) 4/5








C) 5/4




D) 3/4




 Oct 20, 2014

Best Answer 

 #1
avatar+23247 
+5

To find sin(2A):

Use formula:  sin(2A) = 2sin(A)cos(A).

Draw the diagram in the third quadrant.

Since the tan(A) = 1/3, the '1' represents the y-value and the '3' represents the x-value; but, since the angle ends in the third quadrant, both the x-value and the y-value are negative.

Using the Pytagorean theorem, the hypotenuse has value √10.

Thus, sin(A) = -1/√10   and  cos(A) has value -3/√10.

sin(2A) = 2(-1/√10)(-3/√10)  = 6/10.

 Oct 20, 2014
 #1
avatar+23247 
+5
Best Answer

To find sin(2A):

Use formula:  sin(2A) = 2sin(A)cos(A).

Draw the diagram in the third quadrant.

Since the tan(A) = 1/3, the '1' represents the y-value and the '3' represents the x-value; but, since the angle ends in the third quadrant, both the x-value and the y-value are negative.

Using the Pytagorean theorem, the hypotenuse has value √10.

Thus, sin(A) = -1/√10   and  cos(A) has value -3/√10.

sin(2A) = 2(-1/√10)(-3/√10)  = 6/10.

geno3141 Oct 20, 2014

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