+185 In the right triangle ABC, with a= 30 degrees, AB= 2. D is chosen on AC so that DC=BC, and from D a line is drawn perpendicular to AB, meeting AB at K. Show DBK = 15degrees and by finding the lengths of the various lines.
+36916 I hope the image makes it. (Look at the bottom ...left and right) Angle B = 180-90-30 =60 degrees
Angle D2 = 180-90-30 = 60
Since DC = BC in a right triangle (GIVEN in the problem) then angles D1 and B1 are EQUAL too 180- 90 -2x yields the fact that these two angles are 45 degrees
If ANGLE B is 60 degrees and ANGLE B1 is 45 degrees angle DBK = 60 - 45 = 15 degrees.
All this because DC = BC !
+36916 I hope the image makes it. (Look at the bottom ...left and right) Angle B = 180-90-30 =60 degrees
Angle D2 = 180-90-30 = 60
Since DC = BC in a right triangle (GIVEN in the problem) then angles D1 and B1 are EQUAL too 180- 90 -2x yields the fact that these two angles are 45 degrees
If ANGLE B is 60 degrees and ANGLE B1 is 45 degrees angle DBK = 60 - 45 = 15 degrees.
All this because DC = BC !
+36916 Well, my original answer showed you didn't have to find out many segment lengths to get an answer...here is how to do it by figuring all of the segment lengths.....sorry ...it is handwritten...
