twp aircrafts leave an airport at the same time flying at 750 km/h and 850 km/h. After 2.5 hours, they are 1900 km apart. What is the angle between their flights?
We can use the Law of Cosines to solve this........so we have....
(1900^2 - 1875^2 - 2125^2) / (-2(1875)*2125) = cosA
cos-1 ( (1900^2 - 1875^2 - 2125^2) / (-2(1875)*2125)) = about 56.3°
