+14935 Hello anonymous!
vertex of 6x^2+11x-12=0
The apex is the minimum of the parabola.
ƒ(x) = 6x² + 11x -12 = 0
ƒ'(x) = 12x + 11 = 0 → 12x = - 11 → x(vertex) = - 11 / 12
x(vertex) = -11 / 12 = - 0,916,,,
y(vertex) = 6 * (-11 / 12)² + 11 * (-11 / 12) - 12 = -17,0416...
The apex is located in at
P[vertex] (- 0,916,,, / -17,0416... ) ! Minimum !
Greetings :- )
+14935 Hello anonymous!
vertex of 6x^2+11x-12=0
The apex is the minimum of the parabola.
ƒ(x) = 6x² + 11x -12 = 0
ƒ'(x) = 12x + 11 = 0 → 12x = - 11 → x(vertex) = - 11 / 12
x(vertex) = -11 / 12 = - 0,916,,,
y(vertex) = 6 * (-11 / 12)² + 11 * (-11 / 12) - 12 = -17,0416...
The apex is located in at
P[vertex] (- 0,916,,, / -17,0416... ) ! Minimum !
Greetings :- )
