+23245 Since x / x = 1, if you have a string of multiplications in the numerator and a string of multiplications in the denominator, you can cancel one factor in the numerator with an equal factor in the denominator.
(3x^5) / (5x^7) = (3·x·x·x·x·x) / (5·x·x·x·x·x·x·x)
The five x-factors in the numerator will cancel five x-factors in the denominator; so the answer reduces to:
= (3) / (5·x·x) = 3 / (5x²)
(This can be done, in division, more simply by subtacting the exponents (7 minus 5) and since the greater number of x's is in the denominator, the value of x² is in the denominator.
+23245 Since x / x = 1, if you have a string of multiplications in the numerator and a string of multiplications in the denominator, you can cancel one factor in the numerator with an equal factor in the denominator.
(3x^5) / (5x^7) = (3·x·x·x·x·x) / (5·x·x·x·x·x·x·x)
The five x-factors in the numerator will cancel five x-factors in the denominator; so the answer reduces to:
= (3) / (5·x·x) = 3 / (5x²)
(This can be done, in division, more simply by subtacting the exponents (7 minus 5) and since the greater number of x's is in the denominator, the value of x² is in the denominator.
