what is arcsin(-square root of 2 divided by 2) =
Well you could do it on a calculator.
or
arcsin is only defined for [-pi/2, +pi/2]
It is negative so the angle will be between -pi/2 and 0
Now I am just going to look at
$$\\sin\theta=+\frac{\sqrt2}{2}=+\frac{1}{\sqrt2}\\\\
\theta =\frac{ \pi}{4}\\\\
so\\\\
asin\;\frac{-\sqrt2}{2}=\frac{ -\pi}{4}$$
what is arcsin(-square root of 2 divided by 2) =
Well you could do it on a calculator.
or
arcsin is only defined for [-pi/2, +pi/2]
It is negative so the angle will be between -pi/2 and 0
Now I am just going to look at
$$\\sin\theta=+\frac{\sqrt2}{2}=+\frac{1}{\sqrt2}\\\\
\theta =\frac{ \pi}{4}\\\\
so\\\\
asin\;\frac{-\sqrt2}{2}=\frac{ -\pi}{4}$$