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what is arcsin(-square root of 2 divided by 2) =

 Dec 18, 2014

Best Answer 

 #1
avatar+118609 
+5

what is arcsin(-square root of 2 divided by 2) =

Well you could do it on a calculator.

or

arcsin is only defined for  [-pi/2, +pi/2]

It is negative so the angle will be between  -pi/2 and 0

Now I am just going to look at 

$$\\sin\theta=+\frac{\sqrt2}{2}=+\frac{1}{\sqrt2}\\\\
\theta =\frac{ \pi}{4}\\\\
so\\\\
asin\;\frac{-\sqrt2}{2}=\frac{ -\pi}{4}$$

 Dec 18, 2014
 #1
avatar+118609 
+5
Best Answer

what is arcsin(-square root of 2 divided by 2) =

Well you could do it on a calculator.

or

arcsin is only defined for  [-pi/2, +pi/2]

It is negative so the angle will be between  -pi/2 and 0

Now I am just going to look at 

$$\\sin\theta=+\frac{\sqrt2}{2}=+\frac{1}{\sqrt2}\\\\
\theta =\frac{ \pi}{4}\\\\
so\\\\
asin\;\frac{-\sqrt2}{2}=\frac{ -\pi}{4}$$

Melody Dec 18, 2014

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