+0  
 
0
337
2
avatar

what is $${\frac{{\mathtt{dy}}}{{\mathtt{dx}}}}$$ when $${{\mathtt{e}}}^{\left({\mathtt{x}}{\mathtt{\,\times\,}}{\mathtt{y}}\right)} = {\mathtt{x}}{\mathtt{\,\small\textbf+\,}}{\mathtt{y}}$$?

Guest Mar 19, 2015

Best Answer 

 #1
avatar+80935 
+10

exy  = x + y    

Using implicit differentiation, we have

yexy + xy'exy  = 1 + y'

y' ( xexy - 1) = 1 - yexy

y' = [ 1 - yexy  ] / [ xexy - 1]  

 

  

CPhill  Mar 19, 2015
Sort: 

2+0 Answers

 #1
avatar+80935 
+10
Best Answer

exy  = x + y    

Using implicit differentiation, we have

yexy + xy'exy  = 1 + y'

y' ( xexy - 1) = 1 - yexy

y' = [ 1 - yexy  ] / [ xexy - 1]  

 

  

CPhill  Mar 19, 2015
 #2
avatar+91435 
+5

Thanks Chris,

I really need practice at these so it is great when they come onto the forum.

I even got the same answer as you - isn't that great :)

 

Thanks anon for giving us this question :)

Melody  Mar 19, 2015

6 Online Users

avatar
We use cookies to personalise content and ads, to provide social media features and to analyse our traffic. We also share information about your use of our site with our social media, advertising and analytics partners.  See details