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What is the equation of the perpendicular bisector of the segment joining points A(2, −2) and B(6, 4)?

 

Hint: Remember, a perpendicular bisector intersects the midpoint of segment AB full stop

 Jul 9, 2016

Best Answer 

 #1
avatar+33616 
+5

Slope of line joining A and B is (4 - (-2))/(6 - 2) = 3/2  Hence slope of perpendicular line is -2/3

 

Midpoint of A and B is ( (2+6)/2, (-2+4)/2 )  or (4, 1)  

 

Equation of perpendicular bisector is  y - 1 = -(2/3)(x - 4)  or  y = -(2/3)x + 11/3

 

 Jul 9, 2016
 #1
avatar+33616 
+5
Best Answer

Slope of line joining A and B is (4 - (-2))/(6 - 2) = 3/2  Hence slope of perpendicular line is -2/3

 

Midpoint of A and B is ( (2+6)/2, (-2+4)/2 )  or (4, 1)  

 

Equation of perpendicular bisector is  y - 1 = -(2/3)(x - 4)  or  y = -(2/3)x + 11/3

 

Alan Jul 9, 2016
 #2
avatar+118609 
+1

 

Try these steps and see how you go :)

You will learn better if you do quite a bit of it yourself.

You can post your answers (or troubles and someone will look at them for you :)

 

1) find the midpoint of AB

 

2) Find the gradient of AB

 

3)Determine the gradient of the perpendicular to AB

 

4) use the point gradient formula to determine the equation of the line.

 Jul 10, 2016

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