What is the height and volume of a right triangular prism with a base of the triangle = 10 cm, the height of the triangle = 24 cm, and the surface area of the prism = 2640 cm2? The base of the prism is a right triangle.
The area of the triangle at the base = (1/2)(10)(24) = 120 cm^2
And the remaining side of the triangle = √[24^2 + 10^2] = √676 = 26 cm
So we have......
Sa = 2(120) + h(24 + 10 + 26) = 2640 simplify
240 + h(60) = 2640
h(60) = 2400
h = 40 cm
And the volume is just ...... area of the base * height = 120 (40) = 4800 cm^3
The area of the triangle at the base = (1/2)(10)(24) = 120 cm^2
And the remaining side of the triangle = √[24^2 + 10^2] = √676 = 26 cm
So we have......
Sa = 2(120) + h(24 + 10 + 26) = 2640 simplify
240 + h(60) = 2640
h(60) = 2400
h = 40 cm
And the volume is just ...... area of the base * height = 120 (40) = 4800 cm^3