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What is the length of the line segment in the x-y plane with end points (-2, -2) and (2, 3)?

 Jun 5, 2015

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 #1
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We have   ...   √[(-2 - 2)^2 + (-2 - 3)^2]  = √[(-4)^2 + (-5)^2]  = √[16 + 25] = √41

 

 

 Jun 5, 2015
 #1
avatar+128570 
+5
Best Answer

We have   ...   √[(-2 - 2)^2 + (-2 - 3)^2]  = √[(-4)^2 + (-5)^2]  = √[16 + 25] = √41

 

 

CPhill Jun 5, 2015

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