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p(x)=x^3+125

Guest Jul 10, 2017
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x^3  +  125 =  0    can be factored as

 

(x  + 5) ( x^2 - 5x + 25)  = 0

 

The smallest real 0  is found by setting the first factor to 0 and solving

 

x + 5 = 0   subtract 5 from both sides

 

x = -5

 

cool cool cool

CPhill  Jul 10, 2017

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