What is the value of k if x^3 + kx^2 + 7x + 5 is divided by x + 6 and gives a remainder of -1
A.) 5
B.) -7
C.)7
D.)-5
This says that if we put -6 into the function for x, it returns a value of -1......so we have
(-6)^3 + k(-6)^2 + 7(-6)+ 5 = -1 simplify
-216 + 36k - 42 + 5 = -1
-253 + 36k = -1
36k = 252
k = 7
+13 
