What is the value of k if x3 + kx2 + 7x + 5 is divided by x + 6 and gives a remainder of −1?
+118696 What is the value of k if x3 + kx2 + 7x + 5 is divided by x + 6 and gives a remainder of −1?
I am going to use remainder theorum. :)
Here is one of many references for it if you want to take a look.
https://www.mathsisfun.com/algebra/polynomials-remainder-factor.html
f(x)=x3+kx2+7x+5f(−6)=(−6)3+k∗(−6)2+7∗(−6)+5f(−6)=−216+36k−42+5f(−6)=−253+36kButf(−6)=−1−1=−253+36k252=36kk=7
What is the value of k if x3 + kx2 + 7x + 5 is divided by x + 6 and gives a remainder of −1?
[ x^3 + kx^2 + 7x + 5] / [ x + 6] = -1
x=1 and k= -20, or
x=2 and k=-8.75, or
x=3 and k= -6 8/9
+118696 What is the value of k if x3 + kx2 + 7x + 5 is divided by x + 6 and gives a remainder of −1?
I am going to use remainder theorum. :)
Here is one of many references for it if you want to take a look.
https://www.mathsisfun.com/algebra/polynomials-remainder-factor.html
f(x)=x3+kx2+7x+5f(−6)=(−6)3+k∗(−6)2+7∗(−6)+5f(−6)=−216+36k−42+5f(−6)=−253+36kButf(−6)=−1−1=−253+36k252=36kk=7
