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What is the value of k if x3 + kx2 + 7x + 5 is divided by x + 6 and gives a remainder of −1?

Guest Feb 8, 2016

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 #2
avatar+90988 
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What is the value of k if x3 + kx2 + 7x + 5 is divided by x + 6 and gives a remainder of −1?

 

I am going to use remainder theorum.  :)

 

Here is one of many references for it if you want to take a look.

https://www.mathsisfun.com/algebra/polynomials-remainder-factor.html

 

\(f(x)=x^3+kx^2+7x+5\\ f(-6)=(-6)^3+k*(-6)^2+7*(-6)+5\\ f(-6)=-216+36k-42+5\\ f(-6)=-253+36k\\ But\;\;f(-6)=-1\\ -1=-253+36k\\ 252=36k\\ k=7\)

Melody  Feb 8, 2016
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 #1
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What is the value of k if x3 + kx2 + 7x + 5 is divided by x + 6 and gives a remainder of −1?

 

[ x^3 + kx^2 + 7x + 5] / [ x + 6] = -1

 

x=1   and   k= -20, or

x=2   and   k=-8.75, or

x=3   and   k= -6 8/9

Guest Feb 8, 2016
 #2
avatar+90988 
+5
Best Answer

What is the value of k if x3 + kx2 + 7x + 5 is divided by x + 6 and gives a remainder of −1?

 

I am going to use remainder theorum.  :)

 

Here is one of many references for it if you want to take a look.

https://www.mathsisfun.com/algebra/polynomials-remainder-factor.html

 

\(f(x)=x^3+kx^2+7x+5\\ f(-6)=(-6)^3+k*(-6)^2+7*(-6)+5\\ f(-6)=-216+36k-42+5\\ f(-6)=-253+36k\\ But\;\;f(-6)=-1\\ -1=-253+36k\\ 252=36k\\ k=7\)

Melody  Feb 8, 2016
 #3
avatar+78577 
0

Very nice, Melody  !!!!

 

 

 

cool cool cool

CPhill  Feb 8, 2016
 #4
avatar+90988 
0

Thanks Chris  :))

Melody  Feb 8, 2016

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