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What is the value of loge(0.25) ?

 
A

-1.661

B

-1.386

C

-0.721

D

-0.602

 

 
 Jul 26, 2014

Best Answer 

 #2
avatar+4473 
+10

Suppose we have loge(0.25) = x (variable) -->

By properties of logs: e^x = 0.25 -->

Take logs of both sides: log(e^x) = log (0.25) -->

By properties of logs again: x log e = log (0.25) -->

Now, just divide both sides by log e to get log (0.25) / log e = x; x = B, -1.386.

 Jul 26, 2014
 #1
avatar+128578 
0

log(.25) = -0.602

 

 

 

  

 Jul 26, 2014
 #2
avatar+4473 
+10
Best Answer

Suppose we have loge(0.25) = x (variable) -->

By properties of logs: e^x = 0.25 -->

Take logs of both sides: log(e^x) = log (0.25) -->

By properties of logs again: x log e = log (0.25) -->

Now, just divide both sides by log e to get log (0.25) / log e = x; x = B, -1.386.

AzizHusain Jul 26, 2014
 #3
avatar+128578 
0

Aziz's answer is correct..I mistook "loge" as a mispelling of "log"...but I see now that the intent was "ln".....

 

 Jul 27, 2014

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