Quadrilateral ABCD is inscribed in a circle. m A is 64°, m B is (6x + 4)°, and m C is (9x - 1)°. What is m D?
C=180-A=180-64=116
so
9x-1=116
9x=117
x=13
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B=2x+4=6*13+4=82
D=180-82=98 degrees
Since ABCD is inscribed in a circle, A + C = 180°, and B + D = 180°.
So, 64 + 9x - 1 = 180 => x = 13 => D = 98°.
A is 64°, m B is (6x + 4)°, and m C is (9x - 1)°. What is m D?
