Write the expression as a single natural logarithm.

y  =  0.05 - 10ln(0.09)

Enter this expression into this site's calculator to get a decimal approximation.

3 in 3+4 in b........so we have

ln 3³ + ln b⁴  =

ln 27 + ln b⁴ =

ln 27b⁴

3ln3 + 4lnb

A multiplier goes into a logarithm as an exponent:

ln(3^3) + ln(b^4)                 (3^3 = 27)

If the logs are added, it means that the original numbers were multiplied:

ln(27b^4)

Find the value of y for the given value of x.

y=0.05-10 in x; x=0.09