(x+1)^2=x^2(x+7)^2

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(x+1)^2=x^2(x+7)^2

Guest Jan 23, 2015

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Best Answer

$$\\(x+1)^2=x^2(x+7)^2\\
x^2+2x+1=x^2(x^2+14x+49)\\
x^2+2x+1=x^4+14x^3+49x^2\\
x^4+14x^3+49x^2-x^2-2x-1=0\\
x^4+14x^3+48x^2-2x-1=0\\$$

It is not easy to find the roots of this. so I consulted Wolfram|Alpha

Melody Jan 23, 2015

Melody · Answer 1 · 2015-01-23T12:29:27

$$\\(x+1)^2=x^2(x+7)^2\\
x^2+2x+1=x^2(x^2+14x+49)\\
x^2+2x+1=x^4+14x^3+49x^2\\
x^4+14x^3+49x^2-x^2-2x-1=0\\
x^4+14x^3+48x^2-2x-1=0\\$$

It is not easy to find the roots of this. so I consulted Wolfram|Alpha