x^2+ax+b=(x-7)^2-a How do I solve for a and b?

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x^2+ax+b=(x-7)^2-a

How do I solve for a and b?

Guest Jun 9, 2015

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Best Answer

x^2+ax+b=(x-7)^2-a simplify the right side

x^2 + ax + b = x^2 - 14x + 49 - a

So.....a = -14 and b = 49 - a = 49 - 14 = 35

CPhill Jun 9, 2015

CPhill · Answer 1 · 2015-06-09T04:24:34

x^2+ax+b=(x-7)^2-a simplify the right side

x^2 + ax + b = x^2 - 14x + 49 - a

So.....a = -14 and b = 49 - a = 49 - 14 = 35