x^8/x^8+x^0
{x as a pronumeral}
$${\frac{{{\mathtt{x}}}^{{\mathtt{8}}}}{{{\mathtt{x}}}^{{\mathtt{8}}}}}{\mathtt{\,\small\textbf+\,}}{{\mathtt{x}}}^{{\mathtt{0}}}$$
Rosala, this is just one of those silly 1+1 questions. (x8/x8 = 1 and x0 = 1, so this is just 1 + 1).
Answer deleted!
Ooops!I think i hve used some more thinking out here!which wasnt required!Thanks for telling Alan, i think i should delete my answer!Should i!?
