[x/(x-8)]+8=[8/(x-8)]

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Guest Jan 31, 2015

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Best Answer

[x/(x-8)]+8=[8/(x-8)]

The easiest way to do this is to subtract [x/(x-8)] from both sides and write 8 as 8/1.....so we have

8/1 =[8/(x-8)] - [x/(x-8)] =

8/1 = (8 - x)/(x-8) but the right side = -(x -8)/ (x-8) = -1

And 8 can never = -1 .....so this has no solution

CPhill Jan 31, 2015

CPhill · Answer 1 · 2015-01-31T09:09:24

[x/(x-8)]+8=[8/(x-8)]

The easiest way to do this is to subtract [x/(x-8)] from both sides and write 8 as 8/1.....so we have

8/1 =[8/(x-8)] - [x/(x-8)] =

8/1 = (8 - x)/(x-8) but the right side = -(x -8)/ (x-8) = -1

And 8 can never = -1 .....so this has no solution