+0  
 
0
552
3
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y = 0.0629x2 - 0.2765x + 0.3093

then x=?

 Oct 24, 2016
 #1
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0

You can get x, but only in terms of y!!.

 Oct 24, 2016
 #2
avatar+14931 
0

y = 0.0629x2 - 0.2765x + 0.3093 = 0  then x=?

 

\(0.0629 x^{2} - 0.2765x + 0.3093=0 \)

       a                     b                  c

\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)

 

\(x = {0.2765 \pm \sqrt{0.2765^2-4\times 0.0629\times0.3093} \over 2\times0.0629}\)

 

\({\color{blue}x=\frac{0.2765\pm\sqrt{\color{red}-0.00136763}}{2\times0.0629}}\)

 

\({\color{blue}The \ equation \ has \ no \ real \ solution.}\) sad

 Oct 24, 2016
edited by asinus  Oct 24, 2016
edited by asinus  Oct 24, 2016
edited by asinus  Oct 24, 2016
 #3
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0

Solve for x:
y = 0.0629 x^2-0.2765 x+0.3093

0.0629 x^2-0.2765 x+0.3093 = (629 x^2)/10000-(553 x)/2000+3093/10000:
y = (629 x^2)/10000-(553 x)/2000+3093/10000

y = (629 x^2)/10000-(553 x)/2000+3093/10000 is equivalent to (629 x^2)/10000-(553 x)/2000+3093/10000 = y:
(629 x^2)/10000-(553 x)/2000+3093/10000 = y

Multiply both sides by 10000/629:
x^2-(2765 x)/629+3093/629 = (10000 y)/629

Subtract 3093/629 from both sides:
x^2-(2765 x)/629 = (10000 y)/629-3093/629

Add 7645225/1582564 to both sides:
x^2-(2765 x)/629+7645225/1582564 = (10000 y)/629-136763/1582564

Write the left hand side as a square:
(x-2765/1258)^2 = (10000 y)/629-136763/1582564

Take the square root of both sides:
x-2765/1258 = sqrt((10000 y)/629-136763/1582564) or x-2765/1258 = -sqrt((10000 y)/629-136763/1582564)

Add 2765/1258 to both sides:
x = 2765/1258+sqrt((10000 y)/(629)-(136763)/1582564) or x-2765/1258 = -sqrt((10000 y)/629-136763/1582564)

Add 2765/1258 to both sides:
Answer: |x = 2765/1258+sqrt((10000 y)/(629)-(136763)/1582564)    or    x = 2765/1258-sqrt((10000 y)/(629)-(136763)/1582564)

 Oct 24, 2016

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