You have $10,000 to purchase computers and printers. Using the full amount, you can but 10 computers and 10 printers or 12 computers and 2 printers. What is the cost of 1 computer?
+48 10000=10c+10p=10c+10p+2c-8p=12c+2p
From this we can deduce that one computer's cost is equal to the cost of 4 printers, since 8 printers had to be removed to afford 2 extra computers. So c=4p, p=0,25c
This means that if we substitute all 10 printers for their computer value we can find out how much a computer costs.
10c+10*0,25c=10000
10c+2,5c=10000
12,5c=10000
c=10000/12,5
c=800
Answer: One computer costs 800$
