+0  
 
+1
111
2
avatar+545 

https://vle.mathswatch.co.uk/images/questions/question1747.png

 

 

winkwinkwink

lynx7  Apr 12, 2018
edited by lynx7  Apr 12, 2018
edited by lynx7  Apr 12, 2018
edited by lynx7  Apr 12, 2018
 #1
avatar+26829 
+2

The angle between them (call it c) is 125°

 

At 12 knots, after 2 hours ship A will have travelled A = 24 nautical miles.

At 16 knots, sfter 2 hours ship B will have travelled B = 32 nautical miles.

 

Cosine rule:   C2 = A2 + B2 - 2ABcos(c)

 

so distance between ships is C = sqrt(242 + 322 -2*24*32*cos(125°))  nautical miles.

 

I'll leave you to crunch the numbers.

Alan  Apr 12, 2018
edited by Alan  Apr 12, 2018
 #2
avatar+545 
+1

thank you alan

 

 

winkwinkwink

lynx7  Apr 12, 2018
edited by lynx7  Apr 12, 2018
edited by lynx7  Apr 12, 2018

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