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Find 4B if:

Ax-A+Bx+3B= 1

Guest Feb 2, 2016

Best Answer 

 #2
avatar+93866 
+5

I like this question - it is a little different.

 

Good try guest but I think all the Bs should be on the same side :/

 

Ax-A+Bx+3B= 1

 

Bx+3B = 1-Ax+A

B(x+3)=1-Ax+A

4B(x+3)=4(1-Ax+A)

 

\(4B=\frac{4(1-Ax+A)}{x+3}\\\)

Melody  Feb 2, 2016
 #1
avatar
+5

-4/3(Ax-A+Bx-1) =4B

Guest Feb 2, 2016
 #2
avatar+93866 
+5
Best Answer

I like this question - it is a little different.

 

Good try guest but I think all the Bs should be on the same side :/

 

Ax-A+Bx+3B= 1

 

Bx+3B = 1-Ax+A

B(x+3)=1-Ax+A

4B(x+3)=4(1-Ax+A)

 

\(4B=\frac{4(1-Ax+A)}{x+3}\\\)

Melody  Feb 2, 2016

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