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# help

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There are 5 girls and 5 boys in a chess club. The club holds a round-robin tournament in which every player plays against every other player exactly once.

What fraction of the games are boy-versus-boy? Enter your answer as a fraction in simplified form.

Jan 17, 2018

### 6+0 Answers

#1
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Boy-Boy  =  C(5,2)  =  10 games

Girl-Girl = C(5,2)  =  10 games

Boy-Girl  =  5 * 5  =  25 games

So..... Boy - Boy  =

[ 10 ]  /  [ 10 + 10 + 25 ]  =

10 / 45  =

2 / 9

Jan 17, 2018
edited by CPhill  Jan 17, 2018
edited by CPhill  Jan 17, 2018
#2
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that was incorrect but i dont know why

SmartMathMan  Jan 17, 2018
edited by SmartMathMan  Jan 17, 2018
#3
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i figured it out you simplified it wrong

SmartMathMan  Jan 17, 2018
#4
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as a side note both problems i needed help with you got wrong but only because of little mistakes. Maybe pay a little more attetion? thx for your help i just needed some and i figured it out anyway. I hope that feedback helped

SmartMathMan  Jan 17, 2018
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Fixed now....I'm trying to answer too many questions at once....LOL!!!

Jan 17, 2018
#6
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You fixed it. Thx i know. I dont want to  be complaining rather helping. its a struggle i can tell. thx for all the help! :-)

Jan 17, 2018
edited by SmartMathMan  Jan 17, 2018
edited by SmartMathMan  Jan 17, 2018