There are 5 girls and 5 boys in a chess club. The club holds a round-robin tournament in which every player plays against every other player exactly once.

What fraction of the games are boy-versus-boy? Enter your answer as a fraction in simplified form.

SmartMathMan
Jan 17, 2018

#1**0 **

Boy-Boy = C(5,2) = 10 games

Girl-Girl = C(5,2) = 10 games

Boy-Girl = 5 * 5 = 25 games

So..... Boy - Boy =

[ 10 ] / [ 10 + 10 + 25 ] =

10 / 45 =

2 / 9

CPhill
Jan 17, 2018

#4**+1 **

as a side note both problems i needed help with you got wrong but only because of little mistakes. Maybe pay a little more attetion? thx for your help i just needed some and i figured it out anyway. I hope that feedback helped

SmartMathMan
Jan 17, 2018

#6**+1 **

You fixed it. Thx i know. I dont want to be complaining rather helping. its a struggle i can tell. thx for all the help! :-)

SmartMathMan
Jan 17, 2018