+0  
 
0
36
1
avatar+418 

Three couples go to the movie theater. They want to seat people together for maximum enjoyment, but instead they randomly file into a row with six seats. What is the probability that they sit in a socially optimal configuration, in which each person is sitting next to his or her partner?

Logic  Nov 2, 2018
 #1
avatar+93911 
+1

There are 3! ways to sit the partners,then for each of these there are 2 ways to sit the couples. that is 2^3

so that is 3!*8=48 ways

 

Another way to look at it is

there are 6 people to chose from for the first seat

the spouse sits next to them

there are 4 people for the next seat

the spouse sits next to them.

there are 2 people left

the spouse sits last.

number of ways = 6*1*4*1*2*1 = 48 ways

Melody  Nov 3, 2018

31 Online Users

avatar
avatar
avatar

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.