In \(\triangle PQR\), we have \(\angle P = 30^\circ\), \(\angle Q = 60^\circ\), and \(\angle R = 90^\circ\). Point X is on \(\overline{PR}\) such that \(\overline{QX}\) bisects \(\angle PQR\). If PQ=12, then the area of is \(\mathcal A\). What is \(\mathcal A^2\)?
