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In \(\triangle PQR\), we have \(\angle P = 30^\circ\), \(\angle Q = 60^\circ\), and \(\angle R = 90^\circ\). Point X is on \(\overline{PR}\) such that \(\overline{QX}\) bisects \(\angle PQR\). If PQ=12, then the area of is \(\mathcal A\). What is \(\mathcal A^2\)?

 Sep 2, 2019
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Here's a pic:

 

 

If  PQ = 12 ,  then the area of              is \(\mathcal A\)

 

Is something supposed to go in the blank?

 Sep 2, 2019

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