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Find the equation of a parabola whose vertex is at (−1, 7), whose axis of symmetry is x = −1, and whose y-intercept is (0, 10). Write your answer in vertex form.

 Feb 20, 2021

Best Answer 

 #1
avatar+944 
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We know the vertex, so we can write the equation in vertex form: \(y = a(x+1)^2 + 7\)

 

The y-intercept is (0, 10), so plug that point in: \(10 = a + 7\)

 

So, a is equal to 3, and we now have the equation: \(y = 3(x+1)^2 + 7\)

 Feb 20, 2021
 #1
avatar+944 
+1
Best Answer

We know the vertex, so we can write the equation in vertex form: \(y = a(x+1)^2 + 7\)

 

The y-intercept is (0, 10), so plug that point in: \(10 = a + 7\)

 

So, a is equal to 3, and we now have the equation: \(y = 3(x+1)^2 + 7\)

CubeyThePenguin Feb 20, 2021

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