Find the equation of a parabola whose vertex is at (−1, 7), whose axis of symmetry is x = −1, and whose y-intercept is (0, 10). Write your answer in vertex form.
+1224 We know the vertex, so we can write the equation in vertex form: \(y = a(x+1)^2 + 7\)
The y-intercept is (0, 10), so plug that point in: \(10 = a + 7\)
So, a is equal to 3, and we now have the equation: \(y = 3(x+1)^2 + 7\)
+1224 We know the vertex, so we can write the equation in vertex form: \(y = a(x+1)^2 + 7\)
The y-intercept is (0, 10), so plug that point in: \(10 = a + 7\)
So, a is equal to 3, and we now have the equation: \(y = 3(x+1)^2 + 7\)
