+0

+1
58
2 dont understand pleasae explain and need asap thank you and please.

Dec 10, 2020

#1
+2

Don't see how this is possible

The center would have to be  (0,0)  since the  foci    are (0, ±10)  = (0,  ±c)

The hyperbola   opens up/down  and has the form

y^2/a^2  - x^2/b^2   =  1

The equation  for the asymptotes  is    y  =   ±(a/b) x

So......c =  the distance  from the center to the foci   =   sqrt  [ a^2 + b^2 ] =  sqrt  [ 3^2 + 4^2] = sqrt [ 25] =  5

So....the foci should be   at  (0,  ±5)

And the vertices  are  (0,  ±3)

And the equation  is

y^2/ 3^2    - x^2/4^2    =1     →   y^2/9  - x^2/16   =  1

Here's a graph :  https://www.desmos.com/calculator/ciaausrfvm   Dec 10, 2020
#2
-1

EIGHT questions posted already today, Cdortch.      If you REALLY don't understand how to attempt ANY of them or ANY parts of them, you are in a class too dvanced for your current skill level...... you need to go back and review/study your assignments to get a grasp of the concepts before posting all of your homework online.    We are not here to do your homework for you.  We are here to assist you with occasional gaps in understanding that you may have...but you should attemt to answer the questions on your own.....

Dec 10, 2020