Please Help. I will appreciate it anyone can help :-D

A = ( 4cos[ pi/4 ]   , 4 sin [ pi /4 ])     =  (4cos 45° , 4sin 45°)  =      (4 / sqrt( 2)  , 4/sqrt ( 2 )  )

B =  (3 cos [ 5pi/12 ],  3sin [5pi/12 ] )  =  (3cos 75° , 3sin 75°)  = 

(  3 [  sqrt (3) - 1 ] / [ sqrt (8)]  ,  3 [ sqrt (3) + 1] / [sqrt (8)]   )

C = ( 2, pi/12)  =  (2 cos 15° , 2sin 15°) =   (2 sin 75° , 2cos 75°) =  

( 2 [sqrt (3) + 1]/ [sqrt (8)]  ,  2[sqrt (3) -1 ]  / {sqrt (8)  ] 

Vinculum ...   Do you want   AB^2  , AC^2  and BC^2  ??

Or do you mean  (AB)^2 , (AC)^2  and  (BC)^2   ??

Also....these are real points......there shouldn't be any  "i"    involved