A = ( 4cos[ pi/4 ] , 4 sin [ pi /4 ]) = (4cos 45° , 4sin 45°) = (4 / sqrt( 2) , 4/sqrt ( 2 ) )
B = (3 cos [ 5pi/12 ], 3sin [5pi/12 ] ) = (3cos 75° , 3sin 75°) =
( 3 [ sqrt (3) - 1 ] / [ sqrt (8)] , 3 [ sqrt (3) + 1] / [sqrt (8)] )
C = ( 2, pi/12) = (2 cos 15° , 2sin 15°) = (2 sin 75° , 2cos 75°) =
( 2 [sqrt (3) + 1]/ [sqrt (8)] , 2[sqrt (3) -1 ] / {sqrt (8) ]
Vinculum ... Do you want AB^2 , AC^2 and BC^2 ??
Or do you mean (AB)^2 , (AC)^2 and (BC)^2 ??
Also....these are real points......there shouldn't be any "i" involved