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Mr. Mudd gives each of his children $2000 to invest as part of a friendly family competition. The competition will last 10 years. The rules of the competition are simple. Each child can split up his or her $2000 into as many separate investments as they please. The children are encouraged to do their research on types of investments. The initial investments made may not be changed at any point during the 10 years; no money may be added and no money may be moved. Whichever child has made the most money after 10 years will be awarded an additional $10,000.

The table shows the investment made by each of Mr. Mudd’s children, and what happened to their investment over the decade long friendly competition.


Child

Performance of investments over the course of the competition



Albert

$1000 earned 1.2% annual interest compounded monthly

$500 lost 2% over the course of the 10 years

$500 grew compounded continuously at rate of 0.8% annually

Marie

$1500 earned 1.4% annual interest compounded quarterly

$500 gained 4% over the course of 10 years

Hans

$2000 grew compounded continuously at rate of 0.9% annually

Max

$1000 decreased in value exponentially at a rate of 0.5% annually

$1000 earned 1.8% annual interest compounded biannually (twice a year)


What is the balance of Albert’s $2000 after 10 years?


What is the balance of Marie’s $2000 after 10 years?


What is the balance of Hans’ $2000 after 10 years?


What is the balance of Max’s $2000 after 10 years?


Who is $10,000 richer at the end of the competition?

 Dec 12, 2019
edited by Calchelp211  Dec 12, 2019
 #1
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How...or what have you attempted to do to answer this long question?

 Dec 12, 2019
 #2
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is this homework?

 Dec 12, 2019
 #3
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Why do you need an answer so quickly?  Are you just trying to get us to do your homework for you?

 Dec 12, 2019
 #4
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Example Albert:

$1000 earned 1.2% annual interest compounded monthly          =   1000 (1+.001)120  

                                                                                                                 (periodic interest = .012/12 ,n is periods = 10yr x 12 mos)

 

$500 lost 2% over the course of the 10 years                                =    500 (.98)

$500 grew compounded continuously at rate of 0.8% annually     =  500 e.008(10)        10 years    interest .008 (in decimal form)

  

   Add these three to see how Albert did with his investments

 Dec 12, 2019
 #5
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Would the answer be 2159.43

Calchelp211  Dec 13, 2019
edited by Calchelp211  Dec 13, 2019

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