+0

-1
285
15
+226

Find all real solutions for in $$2\left(2^x-\:1\right)\:x^2\:+\:\left(2^{x^2}-2\right)x\:=\:2^{x+1}\:-2$$

Apr 11, 2020

#1
+113240
0

do you mean

$$2^{x^2}=2^{(x^2)}\qquad or \qquad 2^{x^2}=(2^x)^2$$

Apr 11, 2020
#2
+226
+1

Sorry for the confusion, it is the first one.

littlemixfan  Apr 11, 2020
#3
+113240
0

Yes that is what I thought but I still do not know how to solve it.

Melody  Apr 11, 2020
#4
+113240
0

Have you tried entering it into Wolfram|Alpha?

Apr 11, 2020
#5
+226
+1

I have the answers as 1,-1,0 but using WolframAlpha, they don't give steps. And I want the steps to getting to this answer.

littlemixfan  Apr 11, 2020
#6
+226
+1

It says that I have to pay to get the steps.

littlemixfan  Apr 11, 2020
#7
+113240
0

Yes, it gets expensive if you want the steps....

Apr 11, 2020
#8
+226
0

do you know a way to get the steps for free? I have tried on other websites such as Symbolab but they all come out as error, and that they cannot solve this equation.

littlemixfan  Apr 11, 2020
#9
+113240
0

No, sorry, I have no idea.

Apr 11, 2020
#10
+226
0

If you ever find a way to solve it, could you please let me know

littlemixfan  Apr 11, 2020
#11
+113240
0

Yes, will do.

That goes both ways if anyone finds an answer in the near future.

Melody  Apr 11, 2020
#12
+113240
+2

Here is a graphical solution.

Maybe it can be used to get ideas.

Apr 11, 2020
#13
+226
0

Thank you! This problem is really making me on edge. :) :(

littlemixfan  Apr 11, 2020
#14
+32141
+2

See how I approached this problem here: https://web2.0calc.com/questions/help-please_7362#r4

Apr 11, 2020
#15
+226
0

Thank you very much!!

littlemixfan  Apr 11, 2020