+0  
 
-1
74
15
avatar+95 

Find all real solutions for in \(2\left(2^x-\:1\right)\:x^2\:+\:\left(2^{x^2}-2\right)x\:=\:2^{x+1}\:-2\)
 

 Apr 11, 2020
 #1
avatar+109486 
0

Could you please clarify.

 

do you mean

 

\(2^{x^2}=2^{(x^2)}\qquad or \qquad 2^{x^2}=(2^x)^2\)

.
 Apr 11, 2020
 #2
avatar+95 
+1

Sorry for the confusion, it is the first one.

littlemixfan  Apr 11, 2020
 #3
avatar+109486 
0

Yes that is what I thought but I still do not know how to solve it.

Melody  Apr 11, 2020
 #4
avatar+109486 
0

Have you tried entering it into Wolfram|Alpha?

 Apr 11, 2020
 #5
avatar+95 
+1

I have the answers as 1,-1,0 but using WolframAlpha, they don't give steps. And I want the steps to getting to this answer. 

littlemixfan  Apr 11, 2020
 #6
avatar+95 
+1

It says that I have to pay to get the steps.

littlemixfan  Apr 11, 2020
 #7
avatar+109486 
0

Yes, it gets expensive if you want the steps....

 Apr 11, 2020
 #8
avatar+95 
0

do you know a way to get the steps for free? I have tried on other websites such as Symbolab but they all come out as error, and that they cannot solve this equation.

littlemixfan  Apr 11, 2020
 #9
avatar+109486 
0

No, sorry, I have no idea.

 Apr 11, 2020
 #10
avatar+95 
0

If you ever find a way to solve it, could you please let me know

littlemixfan  Apr 11, 2020
 #11
avatar+109486 
0

Yes, will do.

 

That goes both ways if anyone finds an answer in the near future.     laugh

Melody  Apr 11, 2020
 #12
avatar+109486 
+2

Here is a graphical solution.

Maybe it can be used to get ideas.

 

https://www.desmos.com/calculator/k5ajzn7fa8      (direct link)

 

 

 Apr 11, 2020
 #13
avatar+95 
0

Thank you! This problem is really making me on edge. :) :(

littlemixfan  Apr 11, 2020
 #14
avatar+29978 
+2

See how I approached this problem here: https://web2.0calc.com/questions/help-please_7362#r4 

 Apr 11, 2020
 #15
avatar+95 
0

Thank you very much!!

littlemixfan  Apr 11, 2020

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