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In three sets Q, R and S, the following conditions are found.


In Q ∩ R there are 9 elements.


In Q ∩ S there are 4 elements.


In R ∩ S there are 11 elements.


If (Q ∩ R) ∪ (Q ∩ S) ∪ (R ∩ S) includes 18 elements, how many elements are in Q ∩ R ∩ S?

 

 

 

 

Thanks for viewing my problem. 

(Cphill, move your eyes over on this question plz)

 Apr 25, 2021
edited by MathyGoo13  Apr 25, 2021
 #1
avatar+118667 
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Don't know how to solve this one, MG.......maybe someone else does....(sorry  !!! )

 

 

cool cool cool

 Apr 25, 2021
 #2
avatar+130 
+1

No worries!

MathyGoo13  Apr 25, 2021
 #3
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Hello :))

 

In Q and R there are 9. 

In Q and S there are 4. 

In R and S there are 11. 

Combined, there are 18 elements, so there are 3 elements that are the same (9+4+11-18)/2. 

I find it easier to visualize it through a venn diagram. 

 

=^._.^=

 Apr 26, 2021
 #4
avatar+130 
+1

Thank you for the reply!

MathyGoo13  Apr 26, 2021
 #5
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You're welcome. :))

 

=^._.^=

catmg  Apr 26, 2021

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