a plane is taking off at an angle of 5 degrees and maintains this angle for a total time of 10 seconds. The plane's speed during this time is 300 feet per second. Determine the altitude the plane has reached and how far the plane is from the take off point.
+128474 The distance traveled by the plane forms the hypotenuse of a right triangle
This equals 300 * 10 = 3000ft
The altitude , A, can be found as
sin (5°) = A / 3000 multiply both sides by 3000
3000* sin(5°) = A ≈ 261.47 ft
And call the distance [ horizontally ] from the takeoff point , D
So we have
cos ( 5°) = D / 3000
3000cos(5°) = D ≈ 2988. ft
