a plane is taking off at an angle of 5 degrees and maintains this angle for a total time of 10 seconds. The plane's speed during this time is 300 feet per second. Determine the altitude the plane has reached and how far the plane is from the take off point.

Guest Nov 19, 2018

edited by
Guest
Nov 19, 2018

#1**+1 **

The distance traveled by the plane forms the hypotenuse of a right triangle

This equals 300 * 10 = 3000ft

The altitude , A, can be found as

sin (5°) = A / 3000 multiply both sides by 3000

3000* sin(5°) = A ≈ 261.47 ft

And call the distance [ horizontally ] from the takeoff point , D

So we have

cos ( 5°) = D / 3000

3000cos(5°) = D ≈ 2988. ft

CPhill
Nov 19, 2018