+0  
 
0
38
1
avatar

a plane is taking off at an angle of 5 degrees and maintains this angle for a total time of 10 seconds. The plane's speed during this time is 300 feet per second. Determine the altitude the plane has reached and how far the plane is from the take off point.

Guest Nov 19, 2018
edited by Guest  Nov 19, 2018
 #1
avatar+92808 
+1

The distance traveled by the plane forms the hypotenuse of a right triangle

This equals 300 * 10  = 3000ft

 

The altitude , A,  can be found as

 

sin (5°)  = A / 3000    multiply both sides by 3000

 

3000* sin(5°)  = A ≈  261.47 ft

 

And call the distance [ horizontally ] from the takeoff point , D

 

So  we have

 

cos ( 5°) = D / 3000

 

3000cos(5°) = D ≈  2988. ft

 

 

 

cool cool cool

CPhill  Nov 19, 2018

10 Online Users

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.