At x = -2 f(x) = 5 (-2^2) + 3 = 23 y = 23
The slope of f(x) is the derivative 10x and at -2 this equals -20
So we have a point -2,23 and slope = -20
y=mx+b form of this line 23 = -20(-2) + b or b = -17
so the tangent line is y = -20x-17 Now just set this equal to g(x)
g(x) = x x = -20x-17 21x=-17 x = -17/21 = -.81
So the point of intersection is -.81 , -..81
Here is a graph:
