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archhunt
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archhunt
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#1
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You would find the Center by averaging your data points (assuming you are talking about statistics), I am uncertain about the spread.
archhunt
Jan 31, 2014
#2
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All points in a circle are equidistant (not sure if you were implying that or not) and my best guess would be that you would just call it the perimeter.
archhunt
Jan 31, 2014
#2
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So for this we can use trig identities.
The one I will be using is:
1 = sin^2(x) + cos^2(x)
because of this we can simplify this equation to:
(cos^2(x))/(cot^2(x)) =
from there we can break up cotangent into:
cot^2(x) = (cos^2(x))/(sin^2(x))
allowing us to have the equation simplify to:
(cos^2(x))/[(cos^2(x))/(sin^2(x))] ---> which you should be able to do yourself
archhunt
Jan 30, 2014