I will put my questions when I can't solve them
thank you a lot for the help. I appreciate it well.i have now understood it after following both procedures. Thanks so much. I am happy to find myself here
thank you a lot for the help. I appreciate it well. But I am confused haha
Log10x = 0.01
x = 10.01
x = 1.023292992
Therefore 0.01 can be written in log as log​101.023292992