integral of 1/(0.3Q) dQ --> we can separate this into two fractions --> 1/(0.3)*(1/Q)
Now, the constant we can take out which becomes 3.33 and then 1/Q becomes ln(Q).
So, t + C + 120 = 3.33ln(Q) --> Divide both sides by 3.33.
t + C + 120 / (3.33) = ln(Q)
e^(t + C + 120 / (3.33)) = Q
50 = e^(0 + C + 120 / (3.33))
50 = e^(120 + C / (3.33))
ln(50) = ln (120 + C / (3.33))
ln(50) = ln (120 + C) - ln(3.33)
ln(50) + ln(3.33) = ln(120 + C)
Hmm, I am stuck here...I took exponents but didn't work out..
