AzizHusain

[] Brackets are used to define intervals

However, if an interval does not contain a specific value, such as 0, but the interval is from 0 to 5 and contains the value of 5, then:

(0, 5]

Note the use of the opening parenthesis.

I assume you mean the square root of 4^3:

sqrt(4^3) =

sqrt(4*4*4) =

sqrt(16*4) =

sqrt(64) =

$$\mathbf{\pm\;8.}$$

I see. Yep, birthdays are great! Packed with lots of fun and happiness! 

5th root of 1.37 is approximately 1.0649865265642762.

Standard deviation refers to how far away data values are from the mean.

For example, if we had data with the following values: 5,5,5,5

The mean is 5*4/4 = 20/4 = 5.

The standard deviation is 0 because all the values are 5.

However, if we had the following: 0,5,5,100

The mean would now be [(0+5+5+100) / 4] = 110 / 4 = 27.5.

Note: The mean is 27.5 and none of the values are exactly 27.5 so our standard deviation is not 0, but...a different number!

[(1.9*106)/(2.61*105)]= 0.7349023900748039 

0.7349023900748039 + 7.99 = 8.7249023900748039.

(9n^5+2n-11)-(11n-7n^5+3)-(5+7n)

Distribute the - sign:

9n^5 + 2n - 11 - 11n + 7n^5 -3 - 5 - 7n

Collect "like" terms:

16n^5 - 16n - 19.

Oh, yes exams are annoying but you can celebrate after your exams are over for a full party day.

Yes, don't worry and you can leave after your exams I guess (depending on your schedule).

There is a very small chance but likely not because you will be provided with an escape pod that will automatically know where to go.