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BlackoutMiIkshake
Username
BlackoutMiIkshake
Score
224
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Questions
58
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58 Questions
0 Answers
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1
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+224
help help
The function f(x) is defined for 1 \le x \le 5 as follows:
f(x) = 2x + 8 if 1 \le x \le 2
f(x) = 13 - 5x if 2 < x \le 3
f(x) = 20 - 14x if 3 < x \le 4
read more ..
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BlackoutMiIkshake
Apr 7, 2026
0
1
1
+224
plz help
Trapezoid ABCD has bases \overline{AB} and \overline{CD}. The extensions of the two legs of the trapezoid intersect at $P$. If $[ABD]=8$ and $[PBC]=8$, then what is $[PAB]$?
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BlackoutMiIkshake
Apr 7, 2026
0
1
1
+224
helphelphelp
Trapezoid ABCD has bases \overline{AB} and \overline{CD}. The extensions of the two legs of the trapezoid intersect at $P$. If $[PBC] = 15$ and $CD = 3 \cdot AD,$ what is $[ABCD]$?
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BlackoutMiIkshake
Apr 7, 2026
0
1
1
+224
i need help CPhil
There exists a polynomial $f(x)$ and a constant $k$ such that
(x^2 - 2x - 5) f(x) = 2x^4 + 19x^3 + kx^2 - 15x - 1.
What is $k?$
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BlackoutMiIkshake
Apr 7, 2026
0
1
1
+224
plz help
Suppose the domain of f is (-1,3). Define the function g by
g(x) = f((x + 1)(x - 2)).
What is the domain of g?
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BlackoutMiIkshake
Apr 7, 2026
0
1
1
+224
help me Cphil
Point P lies in regular hexagon ABCDEF such that [ABP ] = 3, [CDP] = 3, and [EFP] = 3. Compute [BCP].
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BlackoutMiIkshake
Apr 7, 2026
0
1
1
+224
Cphil help me
Regular hexagon ABCDEF is inscribed in rectangle PQRS. If [AFP] = 20 and [ABC] = 25, then find [ABCDEF].
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BlackoutMiIkshake
Apr 7, 2026
0
1
1
+224
CPhill help me
In triangle $ABC$, points $D$ and $F$ are on $\overline{AB},$ and $E$ is on $\overline{AC}$ such that $\overline{DE}\parallel \overline{BC}$ and $\overline{EF}\parallel \overline{CD}$. If $CE =3$ and $DF = 3$, then what is $BD$?
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BlackoutMiIkshake
Apr 7, 2026
0
1
1
+224
help me now
In quadrilateral $BCED$, sides $\overline{BD}$ and $\overline{CE}$ are extended past $B$ and $C$, respectively, to meet at point $A$. If $BD = 8$, $BC = 3$, $CE = 1$, $AC = 19$ and $AB = 13$, then what is $DE$?
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BlackoutMiIkshake
Apr 7, 2026
0
1
1
+224
help help
In triangle $ABC,$ let the angle bisectors be $\overline{BY}$ and $\overline{CZ}$. Given $AB = 12$, $AY = 12$, and $AC = 12$, find $BZ$.
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BlackoutMiIkshake
Apr 7, 2026
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