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cal01
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cal01
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logarithms
trying to solve for x; log(logx to the 10th degree) = 1 ( i'm pretty sure the answer is 10 but, kinda lost on how to get there.. thanks for any help.
----i was thinking it was 10 because, log10(logx)=1 and log10 equals 1 so, 1 times (logx) =1. logx is
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cal01
Nov 19, 2012