Questions 3
Answers 7

Dec 19, 2019

Scroll down for the answer.

Since the three products are the same, it is impossible for one product to have a factor that another does not. 

Therefore, 7 and 5 don't work because they are coprime (don't share any factors) with every other number on the list.

Of course, 0 doesn't work because then one or two products will be zero while the other is a positive number.


The remaining numbers, 1, 2, 3, 4, 6, 8, and 9 , are the possible digits. 


Notice that every number only has factors of 2 and 3. So, separate the numbers into two groups depending on their factors:


factors of 2: (2,4,6,8)


factors of three: (3,6,9)


There are a total of seven factors of 2 and four factors of 3.

This is somewhat hard to explain, but this means that you must put a factor of 2 as G because otherwise one product will always have one more factor of two than another. Since G belongs to only one product, putting a factor of two as G allows the remaining six factors of 2 to be split equally between AxBxC and DxExF.


If you aren't able to completely follow along below, it's fine, as I am just guessing-and-checking. Just scroll down some more.


Try setting 2 as G. Since 8 has three factors and 2 combined with 4 has three factors, set 8 as A and D,F as 4 and 6 respectively.


You will find that this doesn't work. Instead of putting a 2 on the side, put a six as F. Then, set B as 9 and G as 3. This will balance out the factors of three evenly. 


Finally, put one as C and two as G.


My final configuration is (there are many, put they all have 2 as G):

8      3

9  2  4

1      6


Answer: The value of G is 2.

Dec 16, 2019